SOLUTION: 3x-3y+3z=-27 2x+2y+3z=-3 -3x+2y+2z=-3

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Question 119112: 3x-3y+3z=-27
2x+2y+3z=-3
-3x+2y+2z=-3
Answer by Fombitz(13823) About Me  (Show Source):
You can put this solution on YOUR website!
You didn't specify a solution method.
Hopefully a matrix solution is OK.
[A][x]=[b]
where
[A]=%28matrix%283%2C3%2C%0D%0A3%2C-3%2C+3%2C+%0D%0A2%2C2%2C3%2C%0D%0A-3%2C2%2C2%29%29%0D%0A
[x]=%28matrix%283%2C1%2C%0D%0Ax%2Cy%2Cz%29%29%0D%0A
[b]=%28matrix%283%2C1%2C%0D%0A-27%2C-3%2C-3%29%29%0D%0A
We then need to find the inverse of [A]([Ainv]) and matrix multiply by [b] to get [x].
[A][x]=[b]
[x]=[Ainv][b]
[Ainv]=(1/63)*%28matrix%283%2C3%2C%0D%0A-2%2C12%2C+-15%2C+%0D%0A-13%2C15%2C-3%2C%0D%0A10%2C3%2C12%29%29%0D%0A
[Ainv][b]=(1/63)*%28matrix%283%2C3%2C%0D%0A-2%2C12%2C+-15%2C+%0D%0A-13%2C15%2C-3%2C%0D%0A10%2C3%2C12%29%29%0D%0A%2A%28matrix%283%2C1%2C%0D%0A-27%2C-3%2C-3%29%29
[x]=%28matrix%283%2C1%2C%0D%0A1%2C5%2C-5%29%29%0D%0A
x=1
y=5
z=-5