SOLUTION: Determinar una raíz de la siguiente ecuación de variable “x”: x2 + (3a - 2b)x - 6ab = 0

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Question 1184237: Determinar una raíz de la siguiente ecuación
de variable “x”: x2 + (3a - 2b)x - 6ab = 0
Found 3 solutions by ikleyn, MathLover1, MathTherapy:
Answer by ikleyn(52788)   (Show Source): You can put this solution on YOUR website!
.
Determine roots of the following equation
x2 + (3a - 2b)x - 6ab = 0
~~~~~~~~~~~~~~~~~~ 


Your starting equation is

    x^2 + (3a  -  2b)x  -  6ab = 0


Make factoring

   (x + 3a)*(x - 2b) = 0.


The roots (the solutions) are  x = -3a;  x = 2b.      ANSWER

Solved.


Happy learning (!)


Come again soon (!)



Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!


in your case (en tu caso):











solutions (soluciones):
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Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Determinar una raíz de la siguiente ecuación
de variable “x”: x2 + (3a - 2b)x - 6ab = 0


Using the "ac" method, we determine whcih 2 factors, when multiplied, gives "ac," or - 6ab. 

Furthermore, the same 2 factors sum to "b", or 3a - 2b. These 2 factors are: + 3a and - 2b

Rewrite the equation, substituting + 3ax - 2bx for (3a - 2b)x, to get: 

x(x + 3a) - 2b(x + 3a) = 0

(x - 2b)(x + 3a) = 0

x - 2b = 0          OR          x + 3a = 0 ----- Setting each factor equal to 0.

           OR               

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