SOLUTION: A chemical company makes two brands of antifreeze. The first brand is 30% pure antifreeze, and the second brand is 60% pure antifreeze. In order to obtain 90 gallons of a mixture t

Question 1179771: A chemical company makes two brands of antifreeze. The first brand is 30% pure antifreeze, and the second brand is 60% pure antifreeze. In order to obtain 90 gallons of a mixture that contains 55% pure antifreeze, how many gallons of each brand of antifreeze must be used?
Found 2 solutions by ewatrrr, josgarithmetic:
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!

Hi .30(90-x) + .60x = .55(90) x = .25(90)/.30 = 75gal 60% and 15gal 30% 4.5 + 45 = 49.5 checks. Wish You the Best in your Studies.

Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
Mixing 30% and 60% antifreezes
to make 90 gallons of 55% antifreeze

v gallons of the 60% antifreeze

-

------gallons of the 60%
-
------gallons of the 30%
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