SOLUTION:
The length of a rectangle is 8 inches more than twice its widths. If the perimeter of the rectangle is 64 in, find the width of the rectangle.
Algebra.Com
Question 117402:
The length of a rectangle is 8 inches more than twice its widths. If the perimeter of the rectangle is 64 in, find the width of the rectangle.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
L=2W+8
2(2W+8)+2W=64
4W+16+2W=64
6W=64-16
6W=48
W=48/6
W=8 ANSWER.
L=2*8+8
L=16+8
L=24.
PROOF
2*24+2*8=64
48+16=64
64=64
RELATED QUESTIONS
The length of a rectangle is 8 in. more than twice its width. If the perimeter of the... (answered by hailu,checkley75)
The length of a rectangle is 8 in. more than twice its width. If the perimeter of the... (answered by checkley75)
the length of a rectangle is 8 inches more than its width. the perimeter of the rectangle (answered by solver91311)
The length of a rectangle is 8 inches more than twice its width. If the perimeter of the (answered by Paul)
The length of a rectangle is 8 inches more than twice its width. If the perimeter of the (answered by fractalier,Earlsdon)
The length of a rectangle is 8 in. more than twice it's width. If the perimeter of the... (answered by pwac,jmg)
The Perimeter of a rectangle is 24 inches.Find the dimensions if its length is 3 inches... (answered by Annabelle1,acchs_cheerleader)
The length of a rectangle is 8 more inches than twice its width. If the perimeter of the (answered by THANApHD)
The length of a rectangle is 8 inches more than twice its width. If the perimeter of the... (answered by checkley71,funmath)