SOLUTION: Whatis the solution in this problem? The distance from the center of the seesaw inversely as the weight of a person .jb who weighs 50kg sits 3 feet from the fulcrum.how far from th
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Question 1172967: Whatis the solution in this problem? The distance from the center of the seesaw inversely as the weight of a person .jb who weighs 50kg sits 3 feet from the fulcrum.how far from the fulcrum must jp sit in order to balance withjb if weighs 35kg? Answer by ikleyn(52788) (Show Source):
The seesaw equilibrium equation is THIS
50*3 = 35*x,
where x is the unknown distance from the fulcrum.
From the equation,
x = feet.
Use your calculator.
Solved.
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This problem was posted to this forum couple of weeks ago, and I just solved it once at that time
(with these very strange names of the participants).
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When the problem composers can not invent nothing more original, they use these or similar strange names.
Then other people, who read their posts, start thinking if these writers are Ok or, may be, they need an urgent medical help . . .
