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3x + 2y = 120 (1)
2x + 4y = 160 (2)
Divide eq(2) by 2 (both sides). Keep equation (1) as is. You will get
3x + 2y = 120 (1')
x + 2y = 80 (2')
Now subtract eq(2') from eq(1'). You will get
2x = 120 - 80 = 40
x = = 40/2 = 20.
Then from equation (2'),
20 + 2y = 80
2y = 80 - 20 = 60
y = 60/2 = 30.
ANSWER. 20 yards in the lace ribbon roll and 30 yards in the satin ribbon roll.
Solved.