𝑝1 + 3𝑝2 + 3𝑝3 = 32 (1) 𝑝1 + 4𝑝2 + 3𝑝3 = 37 (2) 𝑝1 + 3𝑝2 + 4𝑝3 = 35 (3) From equation (3), subtract equation (1). You will get p3 = 35 - 32 = 3. (4) Next, from equation (2), subtract equation (1). You will get p2 = 37 - 32 = 5. Sunbstitute the found values p2= 5, p3 = 3 into equation (1). You will get p1 + 3*5 + 3*3 = 32 which implies p1 = 32 - 3*5 - 3*3 = 8. ANSWER. p1= 8, p2= 5, p3= 3.