SOLUTION: 1,000 (3,500) + 200 (0) + 1,900 (85% P) + 100 (P) = 11,100,000

Algebra.Com
Question 116940:
1,000 (3,500) + 200 (0) + 1,900 (85% P) + 100 (P) = 11,100,000

Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
1,000*3,500+200*0+1,900*.85P+100P=11,100,000
3,500,000+0+1,615P+100P=11,100,000
1,715P=11,100,000-3,500,000
1,715P=7,600,000
P=7,600,000/1,715
P=4,431.4868 ANSWER.

RELATED QUESTIONS

EVALUATING R&D PROJECTS AT WESTCOM SYSTEMS PRODUCTS COMPANY West-Com Systems Products... (answered by ikleyn)
The statements of financial position of 3 companies on 31 December 2020 were as follows; (answered by ikleyn)
H. LTD consolidated financial statement on 31 December 2020 was as follows; Credit sales (answered by ikleyn)
TL Ltd is a multinational construction company with subsidiary organisations all around... (answered by ikleyn)
PVA = 80,000/(1.08) + 90,000/(1.08)2 + 100,000/(1.08)3 = ? PVB = 60,000/(1.08) +... (answered by greenestamps)
Not sure what to do. The following table represents the number of koala bears alive... (answered by ikleyn)
The profits of a corner store for 6 days are 2,000 pesos, 3,000 pesos, 1,200 pesos, 6,000 (answered by Boreal)
A man has an investment of 13,760.00 in cash for equipment. His estimates of the year... (answered by Theo)
1) Use the Critical Values of t table to approximate the p-value for the t statistic in... (answered by ikleyn)