SOLUTION: CAN SOMEONE HELP ME SOLVE THIS GRAPHING?
1. DESCRIBE THE TRANSFORMATIONSON ON A GRAPH OF f(x)=e^x. State the placement of the horizonal asympotote and y-intercept after the trans
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Question 116009: CAN SOMEONE HELP ME SOLVE THIS GRAPHING?
1. DESCRIBE THE TRANSFORMATIONSON ON A GRAPH OF f(x)=e^x. State the placement of the horizonal asympotote and y-intercept after the transformation. For example,"left 1" or "rotated about the y-axis" are descriptions
a) g(x)=e^x+3
description of transformation:
Horizonal asymptote:
y-intercept in (x,y) form:
b)H(x)=e^-x
description of transformation:
Horizonal asymptote:
y-intercept in (x,y)form
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
a)
Description of transformation:
Remember, is the same as . So this means .
So when we say , we're also saying (replace with y). So this means we're adding 3 to each y value which graphically shows us that we're shifting each y value up 3 units.
----------------------------
Answer:
So the transformation simply shifts the entire curve up 3 units.
Notice if we graph and , we get
Graph of (red) and (green)
and we can visually verify the transformation
Horizontal Asymptote:
Now if we found the asymptote of , we would find that the asymptote is . Since we're translating each point on up 3 units, we're also translating the horizontal asymptote up 3 units.
----------------------------
Answer:
So the new horizontal asymptote is .
Also, you can visually verify this answer by looking at the graph above
y-intercept in (x, y) form:
If we let x=0 and plug it into , we get
Plug in x=0
Raise e to the zeroth power to get one. Remember any number x to the zeroth power is always one (ie )
So for the y-intercept is (0,1)
Now if translates each y value up 3 units, then simply add 3 to the y-coordinate of the y-intercept to get
(0,1+3)---->(0,4)
----------------------------
Answer:
So the new y-intercept is (0,4)
Once again, you can visually verify this answer by looking at the graph above
b)
Description of transformation:
Looking at , notice how the exponent is negated. So let's see what affect this transformation has on ,
Start with the given transformation
Plug in x=-2
Negate to get 2
Notice if we plug in x=2 into , we get
--------
Start with the given transformation
Plug in x=-1
Negate to get 1
Remove the exponent of 1
Notice if we plug in x=1 into , we get
So if we take the opposite of x (to get -x), and plug that into g(x), we'll get the same f(x) answer.
----------------------------------
Answer:
So what this does is simply reflect the entire graph over the y-axis
Notice if we graph and , we get
Graph of (red) and (green)
and we can visually verify the transformation
Horizontal Asymptote:
Since we reflected the graph with respect to the y-axis, the horizontal asymptote of is the same as (you can see this from the graph above)
----------------------------------
Answer:
So the horizontal asymptote is
Note: you can visually verify this answer by looking at the graph above
y-intercept in (x, y) form:
Since the line of symmetry between the two graphs is the line x=0 (ie the y axis), this means that the point that intersects with the y-axis is reflected to itself. So essentially the y-intercept does not change also. Once again, you can visually verify this using the graph above.
----------------------------------
Answer:
So the y-intercept is (0,1)
Once again, you can visually verify this answer by looking at the graph above
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