SOLUTION: Use two equations in two variables to solve the application. Two pairs of shoes and four pairs of socks cost $111, and three pairs of shoes and five pairs of socks cost $160. Fi

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Use two equations in two variables to solve the application. Two pairs of shoes and four pairs of socks cost $111, and three pairs of shoes and five pairs of socks cost $160. Fi      Log On


   



Question 1152318: Use two equations in two variables to solve the application.
Two pairs of shoes and four pairs of socks cost $111, and three pairs of shoes and five pairs of socks cost $160. Find the cost of a pair of socks.

Found 3 solutions by VFBundy, MathTherapy, josgarithmetic:
Answer by VFBundy(438) About Me  (Show Source):
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Cost of pair of socks = x
Cost of pair of shoes = y

4x + 2y = 111
5x + 3y = 160

Multiply the first equation by -1.5:

-1.5(4x + 2y) = -1.5(111)

-6x - 3y = -166.5

Now, your two equations are:

-6x - 3y = -166.5
5x + 3y = 160

Add the two equations together:

-x = -6.5

Solve for x:

x = 6.5

Cost of pair of socks = x = 6.5...or $6.50

Answer by MathTherapy(10552) About Me  (Show Source):
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Use two equations in two variables to solve the application.
Two pairs of shoes and four pairs of socks cost $111, and three pairs of shoes and five pairs of socks cost $160. Find the cost of a pair of socks.
Let cost of 1 pair of shoes and 1 pair of socks be B and S, respectively
Then we get: 2B + 4S = 111 ------ eq (i)
Also, 3B + 5S = 160 ------ eq (ii)
B + S = 49_____B = 49 - S ----- Subtracting eq (i) from eq (ii) ----- eq (iii)
2(49 - S) + 4S = 111 ------ Substituting 49 - S for B in eq (i)
98 - 2S + 4S = 111
2S = 13
S, or cost of 1 pair of socks = highlight_green%28matrix%281%2C3%2C+13%2F2%2C+%22=%22%2C+%22%246.50%22%29%29

Answer by josgarithmetic(39617) About Me  (Show Source):
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h, shoes
k, socks
system%282h%2B4k=111%2C3h%2B5k=160%29

3*E1, and 2*E2
system%286h%2B12k=333%2C6h%2B10k=320%29

E1-E2
2k=13
k=13%2F2
highlight_green%28k=6.5%29