# SOLUTION: I'm sturggling with this problem. Any help would be greatly appreciated. Solve the following non-linear system by substitution. x^2+y^2=16 x-2y=0

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: I'm sturggling with this problem. Any help would be greatly appreciated. Solve the following non-linear system by substitution. x^2+y^2=16 x-2y=0      Log On

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 Click here to see ALL problems on Linear-systems Question 115081: I'm sturggling with this problem. Any help would be greatly appreciated. Solve the following non-linear system by substitution. x^2+y^2=16 x-2y=0Found 2 solutions by stanbon, checkley71:Answer by stanbon(57224)   (Show Source): You can put this solution on YOUR website!Solve the following non-linear system by substitution. x^2+y^2=16 x-2y=0 ----------- x = 2y Substitute into the 1st equation to solve for "y": (2y)^2 + y^2 = 16 4y^2 + y^2 = 16 5y^2 = 16 y^2 = 16/5 ------------ y = 4/sqrt(5) = (4/5)sqrt(5) OR y = (-4/5)sqrt5 ----------------- Substitute into x = 2y to get: x = 2[(4/5)sqrt5] = (8/5)sqrt(5) OR x = 2(-4/5)sqrt5 = (-8/5)sqrt(5) ===================== Cheers, Stan H. Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!x-2y=0 or x=2y now substitute 2y for x in the other equation & solve for y. (2y)^2+y^2=16 4y^2+y^2=16 5y^2=16 y^2=16/5 y=4/sqrt5 answer. x-2(4/sqrt5)=0 x-8/sqrt5=0 x=8/sqrt5 answer.