SOLUTION: A chemical company makes two brands of antifreeze. The first brand is 35% pure antifreeze, and the second brand is 60% pure antifreeze. In order to obtain 160 gallons of a mixture

Question 1149424: A chemical company makes two brands of antifreeze. The first brand is 35% pure antifreeze, and the second brand is 60% pure antifreeze. In order to obtain 160 gallons of a mixture that contains 45% pure antifreeze, how many gallons of each brand of antifreeze must be used?
Found 2 solutions by josmiceli, greenestamps:
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = gallons of the 35% antifreeze needed
Let = gallons of the 60% antifreeze needed
-------------------------------------------------------
(1)
(2)
--------------------------------------
(2)
(2)
(2)
Multiply both sides of (1) by and
subtract (1) from (2)
(2)
(1)
------------------------------

and
(1)
(1)
--------------------------
96 gallons of the 35% antifreeze are needed
64 gallons of the 60% antifreeze are needed
--------------------------
check:
(2)
(2)
(2)
(2)
(2)
OK
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!

Mix the two in a ratio determined by where the 45% lies between 35% and 60%.

35 to 45 is 10; 35 to 60 is 25. 45 is 10/25 = 2/5 of the way from 35 to 60.

That means 2/5 of the mixture needs to be the 60% antifreeze.

ANSWER: 2/5 of 160 gallons, or 64 gallons, of the 60% antifreeze; 3/5 of the 160 gallons, or 96 gallons, of the 35% antifreeze.

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