SOLUTION: Find the largest two consecutive even integers such that 100 decreased by three times the first one is greater than twice the second one.

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Question 114839:
Find the largest two consecutive even integers such that 100 decreased by three times the first one is greater than twice the second one.
Answer by checkley71(8403) About Me  (Show Source):
You can put this solution on YOUR website!
LET X & (X+2) BE THE 2 INTEGERS.
100-3*X>2(X+2)
100-3X>2X+4
-3X-2X>4-100
-5X>-96 DIVIDING BY A NEGATIVE INTEGER CHANGES THE > TO A <.
X<-96/-5
X<19.2
THUS THE LARGEST EVEN INTEGER WOULD BE 18.
18+2=20.
PROOF
100-3*18>2*20
100-54>40
46>40