SOLUTION: Find the largest two consecutive even integers such that 100 decreased by three times the first one is greater than twice the second one.

Question 114839:
Find the largest two consecutive even integers such that 100 decreased by three times the first one is greater than twice the second one.
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
LET X & (X+2) BE THE 2 INTEGERS.
100-3*X>2(X+2)
100-3X>2X+4
-3X-2X>4-100
-5X>-96 DIVIDING BY A NEGATIVE INTEGER CHANGES THE > TO A <.
X<-96/-5
X<19.2
THUS THE LARGEST EVEN INTEGER WOULD BE 18.
18+2=20.
PROOF
100-3*18>2*20
100-54>40
46>40
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