SOLUTION:
How much of an alloy that is 10% copper should be mixed with 300 ounces of an
alloy that is 90% copper in order to get an alloy that is 50% copper?
___ ounces
Algebra.Com
Question 114633:
How much of an alloy that is 10% copper should be mixed with 300 ounces of an
alloy that is 90% copper in order to get an alloy that is 50% copper?
___ ounces
Answer by checkley71(8403) (Show Source): You can put this solution on YOUR website!
.1X+.90*300=.5(300+X)
.1X+270=150+.5X
.1X-.5X=150-270
-.4X=-120
X=-120/-.4
X=300 OUNCES OF 10% COPPER IS REQUIRED.
PROOF:
.10*300+.9*300=.5*600
30+270=300
300=300
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