SOLUTION: A ball thrown from a height of 1 meter with an initial upward velocity of 25 m/s. The balls height h (in meters) after t seconds is given by the following h=1+25t-5t^2 . Find all v

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Question 1144482: A ball thrown from a height of 1 meter with an initial upward velocity of 25 m/s. The balls height h (in meters) after t seconds is given by the following h=1+25t-5t^2 . Find all values of t for which the balls height is 11 meters. Round to the nearest hundredth
Answer by ikleyn(52790)   (Show Source): You can put this solution on YOUR website!
.
The ball is at the height 11 meters, when


    1 + 25t - 5t^2 = 11   meters.


Solve this quadratic equation to find "t".


    5t^2 - 25t + 10 = 0

      t^2 - 5t + 2 = 0

       =  = 


       =  = 0.44 seconds (approximately),   and

       =  = 4.56 seconds (approximately).



   


    Plot y =  (red) and y = 11 (green)



Time moment   corresponds to the ball moving up.

Time moment   corresponds to the ball falling down.


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