SOLUTION: Find the equation of the line passing through (2,-1) and (-3,8).

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Find the equation of the line passing through (2,-1) and (-3,8).       Log On


   

Question 1139614: Find the equation of the line passing through (2,-1) and (-3,8).
Found 2 solutions by MathLover1, Alan3354:
Answer by MathLover1(20850) About Me  (Show Source):
You can put this solution on YOUR website!
to find the equation of the line passing through (2,-1) and (-3,8), first use given points to find a slope
m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29
m=%288-%28-1%29%29%2F%28-3-2%29
m=%288%2B1%29%2F-5
m=-9%2F5
now use point slope formula:
y-y%5B1%5D=m%28x-x%5B1%5D%29.......plug in m=-9%2F5,(2,-1)
y-%28-1%29=-%289%2F5%29%28x-2%29
y%2B1=-%289%2F5%29x-2%28-9%2F5%29
y=-%289%2F5%29x%2B18%2F5-1
y=-%289%2F5%29x%2B18%2F5-5%2F5
y=-%289%2F5%29x%2B13%2F5=> your equation



Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Find the equation of the line passing through (2,-1) and (-3,8).
--------

| x   y   1|
| 2  -1   1| = 0
|-3   8   1|

---
x*(-1-8) - y*(2 + 3) + 1*(16-3) = 0
-9x -5y + 13 = 0
===================
It's not "the equation"
It's an equation.