SOLUTION: A bus and a car leave a town at 10:30 AM and travel in opposite directions. The bus travels at an average speed of 50km/hr and the car travels at the average speed of 55km/hr
Let
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Question 1131623: A bus and a car leave a town at 10:30 AM and travel in opposite directions. The bus travels at an average speed of 50km/hr and the car travels at the average speed of 55km/hr
Let t equal the time taken for the journey.
i) Write an expression in t for the distance travelled by bus
ii) Write an expression in t for the distance travelled by the car
iii) write an equation in t to show the time at which the bus and the car are 140km apart
iv) Solve for T
v) If the car and the bus travelled in the same direction, at what time would the car be 30km in front of the bus??
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A bus and a car leave a town at 10:30 AM and travel in opposite directions.
The bus travels at an average speed of 50km/hr and the car travels at the average speed of 55km/hr
:
Let t equal the time taken for the journey.
i) Write an expression in t for the distance travelled by bus
50t
ii) Write an expression in t for the distance travelled by the car
55t
iii) write an equation in t to show the time at which the bus and the car are 140km apart
50t + 55t = 140
105t = 140
iv) Solve for T
t = 140/105
t = 1 hrs which is 1 hr 20 min, 10:30 + 1:20 = 11:50 am
v) If the car and the bus travelled in the same direction, at what time would the car be 30km in front of the bus??
55t - 50t = 30
5t = 30
t = 30/5
t = 6 hrs after 10:30 which is 4:30 pm
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