SOLUTION: 5(x+999) = -7(y+23322)
(2k+1)(y+23322) = k(x+999)
I just need to know which value of "k" will make the equation have infinitely many solutions. Can someone give me a step by step
Algebra.Com
Question 1131389: 5(x+999) = -7(y+23322)
(2k+1)(y+23322) = k(x+999)
I just need to know which value of "k" will make the equation have infinitely many solutions. Can someone give me a step by step because I am lost here. Thank you!
Found 2 solutions by JoelSchwartz, greenestamps:
Answer by JoelSchwartz(130) (Show Source): You can put this solution on YOUR website!
5(x+999)=-7(y+23322)
(x+999)=(-7(y+23322))/5
((x+999))/(y+23322)=-7/5
(2k+1)(y+23322)=k(x+999)
(2k+1)=k(x+999)/(y+23322)
2k+1=k*-7/5
10k+5=-7k
17k=-5
k=-5/17
Answer by greenestamps(13200) (Show Source): You can put this solution on YOUR website!
Solve each equation for (y+22332)/(x+999):
(1) -->
(2) -->
So
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