Solved by pluggable solver: Solving a linear system of equations by subsitution |
Lets start with the given system of linear equations Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y. Solve for y for the first equation Which breaks down and reduces to Since y equals So when we multiply Now that we know that So this is the other answer So our solution is which can also look like ( Notice if we graph the equations (if you need help with graphing, check out this solver) we get and we can see that the two equations intersect at ( ----------------------------------------------------------------------------------------------- Check: Plug in ( Let So the solution ( Let So the solution ( Since the solution ( this verifies our answer. |
2x + 3y = 78 (1) 6x + 5y = 180 (2) Apply the elimination method. Multiply eq(1) by 3 (both sides). Keep the equation (2) as is. 6x + 9y = 234 (1') 6x + 5y = 180 (2') Now subtract eq(2') from eq(1'). the terms " 6x " will cancel each other, and you will get a single equation for only one unknown "y". (It is how the Elimination method works) 9y - 5y = 234 - 180 4y = 54 y = 54/4 = 13.5. Then from eq(1) 2x = 78 - 3*13.5 = 37.5 ====> x = 37.5/2 = 18.75. Answer. x== 18.75; y = = 13.5.
This is SO, SO, SIMPLE!
2x + 3y = 78 -------- eq (i)
6x + 5y = 180 ------- eq (ii)
- 6x - 9y = - 234 --- Multiplying eq (i) by - 3 ------ eq (iii)
- 4y = - 54 --------- Adding eqs (iii) & (ii)
Now, substitutefor y in eq (i) or (ii) and find the value of x.
An alternative is to ELIMINATE y in the 2 original equations and you'll be able to find x.