SOLUTION: hi! what do x and y equal in this system of linear equation: 2x+3y=78 and 6x+5y=180

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Question 1130668: hi! what do x and y equal in this system of linear equation: 2x+3y=78 and 6x+5y=180
Found 3 solutions by MathLover1, ikleyn, MathTherapy:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!




Solved by pluggable solver: Solving a linear system of equations by subsitution


Lets start with the given system of linear equations




Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.

Solve for y for the first equation

Subtract from both sides

Divide both sides by 3.


Which breaks down and reduces to



Now we've fully isolated y

Since y equals we can substitute the expression into y of the 2nd equation. This will eliminate y so we can solve for x.


Replace y with . Since this eliminates y, we can now solve for x.

Distribute 5 to

Multiply



Reduce any fractions

Subtract from both sides


Combine the terms on the right side



Make 6 into a fraction with a denominator of 3

Now combine the terms on the left side.


Multiply both sides by . This will cancel out and isolate x

So when we multiply and (and simplify) we get



<---------------------------------One answer

Now that we know that , lets substitute that in for x to solve for y

Plug in into the 2nd equation

Multiply

Subtract from both sides

Make 180 into a fraction with a denominator of 2



Combine the terms on the right side

Multiply both sides by . This will cancel out 5 on the left side.

Multiply the terms on the right side


Reduce


So this is the other answer


<---------------------------------Other answer


So our solution is

and

which can also look like

(,)

Notice if we graph the equations (if you need help with graphing, check out this solver)




we get


graph of (red) and (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.


and we can see that the two equations intersect at (,). This verifies our answer.


-----------------------------------------------------------------------------------------------
Check:

Plug in (,) into the system of equations


Let and . Now plug those values into the equation

Plug in and


Multiply


Add


Reduce. Since this equation is true the solution works.


So the solution (,) satisfies



Let and . Now plug those values into the equation

Plug in and


Multiply


Add


Reduce. Since this equation is true the solution works.


So the solution (,) satisfies


Since the solution (,) satisfies the system of equations






this verifies our answer.



Answer by ikleyn(52800)   (Show Source): You can put this solution on YOUR website!
.

            Instead of that nonsensical response from the tutor @MathLover1, i will try to produce something more adequate.


2x + 3y =  78      (1)
6x + 5y = 180      (2)


Apply the elimination method.  Multiply eq(1) by 3 (both sides).  Keep the equation (2) as is.


6x + 9y = 234      (1')
6x + 5y = 180      (2')


Now subtract eq(2') from eq(1'). the terms " 6x " will cancel each other, and you will get a single equation for only one unknown "y".

    (It is how the Elimination method works)


    9y - 5y = 234 - 180

       4y   =   54

        y   =   54/4  = 13.5.


Then from eq(1)   2x = 78 - 3*13.5 = 37.5  ====>  x = 37.5/2 = 18.75.


Answer.  x=  = 18.75;  y =  = 13.5.

Solved.

------------------------

I am very surprised on how the tutor @LoverMath1 treats these problems on solving equation systems.

By applying this "pluggable solver", she turns / transforms / converts very serious educational task of teaching students
into some unreadable and nonsensical text.


Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

hi! what do x and y equal in this system of linear equation: 2x+3y=78 and 6x+5y=180
This is SO, SO, SIMPLE!
2x + 3y = 78 -------- eq (i)
6x + 5y = 180 ------- eq (ii)
- 6x - 9y = - 234 --- Multiplying eq (i) by - 3 ------ eq (iii)
- 4y = - 54 --------- Adding eqs (iii) & (ii)

Now, substitute for y in eq (i) or (ii) and find the value of x.
An alternative is to ELIMINATE y in the 2 original equations and you'll be able to find x.
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