SOLUTION: A basketball team sells tickets that cost​ $10, $20,​ or, for VIP​ seats,​ $30. The team has sold 3281 tickets overall. It has sold 191 more​ $20 tick

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: A basketball team sells tickets that cost​ $10, $20,​ or, for VIP​ seats,​ $30. The team has sold 3281 tickets overall. It has sold 191 more​ $20 tick      Log On


   



Question 1128086: A basketball team sells tickets that cost​ $10, $20,​ or, for VIP​ seats,​ $30. The team has sold 3281 tickets overall. It has sold 191 more​ $20 tickets than​ $10 tickets. The total sales are ​64,510. How many tickets of each kind have been​ sold?
Found 3 solutions by Mtrkcrc, ikleyn, greenestamps:
Answer by Mtrkcrc(8) About Me  (Show Source):
You can put this solution on YOUR website!
So 1 10 dollar tickets are sold and 192 20 dollar tickets were sold and the others are vip tickets to maximise the money made

Answer by ikleyn(52790) About Me  (Show Source):
You can put this solution on YOUR website!
.
Let x = the number of $10 tickets.


Then the number of the $20 tickets is (x+191),

and the number of the $30 tickets is  (3281- x - (x+191)) = (3090-2x).


The "money" equation (the revenue equation) is 


    10x + 20*(x+191) + 30*(3090-2x) = 64510    dollars


Simplify and solve for x:


    10x + 20x + 20*191 - 60x + 30*3090 = 64510

    -30x = 64510 - 20*191 - 30*3090 

    -30x = -32010    ====>  x = 32010%2F30 = 1067.


Answer.  1067 of the $10 tickets;  (1067+191) = 1258 of the $20 tickets;  and  (3090-2*1067) = 956 of the $30 tickets.


Check.   1067*10 + 1258*20 + 956*30 = 64510  dollars.    ! Correct !

Solved.

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For what reason @Mtrkcrc wrote his post and what does it mean is a mystery for me.

In my view, the reader can safely re-direct it into the TRASH section.


Answer by greenestamps(13200) About Me  (Show Source):
You can put this solution on YOUR website!


This is a comment for new tutor @Mtrkcrc.... I hope he sees it.

I see you have answered 6 questions from readers.

I can see from your answers that you know how to answer the questions. However...

(1) In 3 of the 6 problems, you didn't answer the question; you either answered a completely different question by not using some of the given information, or you used numbers that were different from what was given.

(2) In 2 of the other 3 problems, your answers were valid, and correct. But they were probably of little use to the reader, because they were too short, with little or no explanation of WHY you were solving the problems the way you did. Remember that the reader probably has far less knowledge of math than you do; take the time to EXPLAIN the solution process.

(3) Finally, learn to use the { } symbols to show your calculations. The calculation

4950 plus 100 equals 5050

is not as easy to read as if you used math symbols and enclosed it in the sets of curly brackets:

4950%2B100+=+5050

Continue to enjoy helping others learn math; but remember that you are almost certainly talking to someone who knows far less than you about the math.