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Let x = the number of $10 tickets.
Then the number of the $20 tickets is (x+191),
and the number of the $30 tickets is (3281- x - (x+191)) = (3090-2x).
The "money" equation (the revenue equation) is
10x + 20*(x+191) + 30*(3090-2x) = 64510 dollars
Simplify and solve for x:
10x + 20x + 20*191 - 60x + 30*3090 = 64510
-30x = 64510 - 20*191 - 30*3090
-30x = -32010 ====> x = = 1067.
Answer. 1067 of the $10 tickets; (1067+191) = 1258 of the $20 tickets; and (3090-2*1067) = 956 of the $30 tickets.
Check. 1067*10 + 1258*20 + 956*30 = 64510 dollars. ! Correct !
Solved.
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For what reason @Mtrkcrc wrote his post and what does it mean is a mystery for me.
In my view, the reader can safely re-direct it into the TRASH section.