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Let P the number of pennies and N be the number of nickels in the jar.
Then the coins worth is P + 5N cents and the equation is
P + 5N = 920 (1) (cents)
Now, under the "if" scenario, it would be P nickels and N pennies, that would worth 5P + N cents. So, the second equation is
5P + N = 2680 (2) (cents)
Thus you have this system of two equation in 2 unknowns
P + 5N = 920 (1)
5P + N = 2680 (2)
To solve it, from eq(1) express P = 920-5N, and then substitute it into eq(2), replacing P. You will get a single equation for only one unknown N:
5*(920-5N) + N = 2680.
Simplify and solve for N:
4600 - 25N + N = 2680.
-24N = 2680 - 4600
-24N = -1920 ====> N = = 80.
Thus there are 80 nickels in the original collection.
Then the number of pennies is P = 920 - 5N = 920 - 5*80 = 920 - 400 = 520.
Solved.