SOLUTION: one weekend members of a cycling club rode on the KVR trail uphill from penticton on okanagan B.C the uphill climb reduces the cyclists usual average speed by 6km/h and they took 4

Question 1116538: one weekend members of a cycling club rode on the KVR trail uphill from penticton on okanagan B.C the uphill climb reduces the cyclists usual average speed by 6km/h and they took 4 hours to get to Chute lake. On the return trip the downhill ride increased the cyclists usual average speed by 4km/h. the return trip took 2 hours
What is the usual speed?
What is the distance from penticton to chute lake?
Answer by ikleyn(52879) (Show Source): You can put this solution on YOUR website!
.

Let x = the usual speed, in km/h.


Then the condition says

(x-6)*4 = (x+4)*2        <<<---=== stating that each way distances are the same !


4x - 24 = 2x + 8

4x - 2x = 8 + 24

2x = 32  ====>  x =  = 16.


Thus we found usual speed = 16 km/h.


The distance is (x-6)*4 = (16-6)*4 = 10*4 = 40 kilometers.

Solved.

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