SOLUTION: Ally's hotel ordered 200 flowers for annual celebration. They ordered carnations at 1.50 each, roses at 5.75 each, and daisies at 2.60 each. They ordered mostly carnations and 20 f

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Question 1099448: Ally's hotel ordered 200 flowers for annual celebration. They ordered carnations at 1.50 each, roses at 5.75 each, and daisies at 2.60 each. They ordered mostly carnations and 20 fewer roses than daisies. The total order came to 589.50. How many of each type of flowers was ordered?
Found 2 solutions by ikleyn, greenestamps:
Answer by ikleyn(52787)   (Show Source): You can put this solution on YOUR website!
.
Let D be the number of daisies.

Then the number of roses was (D-20).

The carnations were the rest (200 - D - (D-20)) = 180-2D flowers.


The cost for daisies    was  2.60*D (dollars ?)

The cost for roses      was  5.75*(D-20) dollars (?)

The cost for carnations was  1.50*(180-2D).


The "money" equation is 

2.60*D + 5.75*(D-20) + 1.50*(180-2D) =   589.50   dollars (?)   (<<<---=== here I counted all the money)  //5.75 was a typo, obviously . . . 


It is your basic (balance) equation.
As soon as you got it, you completed the setup part of the solution.


You got a single equation for only one unknown D.

Simplify it and solve for D, the number of daisies.


Then calculate the number of other flowers.


Answer by greenestamps(13200)   (Show Source): You can put this solution on YOUR website!


Just pointing out to you that obviously tutor ikleyn didn't mean what she wrote for the "money equation":

2.60*D + 5.75*(D-20) + 1.50*(180-2D) = 5.75 dollars (?)

The equation should of course read
2.60*D + 5.75*(D-20) + 1.50*(180-2D) = 589.50
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