SOLUTION: x1+x2+x3=6 2x1-x2+3x3=4 4x1+5x2-10x3=13

Question 1099131: x1+x2+x3=6
2x1-x2+3x3=4
4x1+5x2-10x3=13
Found 2 solutions by Fombitz, Boreal:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
Use Cramer's rule,

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Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
x1+x2+x3=6
2x1-x2+3x3=4
4x1+5x2-10x3=13
===================Add the first two
3x1+4x3=10; add 5 times the second to the third
14x1+5x3=33
-5 times the first + 4 times the second
-15x1-20x3=-50
56x1+20x3=132
41x1=82
x1=2
2+x2+x3=6
4-x2+3x3=4
4x3=4
x3=1
x2=3
(2, 3, 1)
check in the second and works
check in third and works.

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