SOLUTION: Write the equation of the line through [-17/3, 8/5] that is parallel to the x-axis. * -17/3x+8/5y=0 * y=-17/3x+8/5 * x=-17/3 * y=8/5

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: Write the equation of the line through [-17/3, 8/5] that is parallel to the x-axis. * -17/3x+8/5y=0 * y=-17/3x+8/5 * x=-17/3 * y=8/5       Log On


   

Question 109869This question is from textbook Beginning and Intermediate Algebra
: Write the equation of the line through [-17/3, 8/5] that is parallel to the x-axis.
* -17/3x+8/5y=0
* y=-17/3x+8/5
* x=-17/3
* y=8/5
 This question is from textbook Beginning and Intermediate Algebra

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
Anything that is parallel to the x axis has a slope of 0 (ie m=0). So the equation


y=mx%2Bb

becomes

y=0x%2Bb===>y=b


Now just substitute in y=8%2F5 to get b=8%2F5


So the equation parallel to the x axis going through (-17/3, 8/5) is

y=8%2F5