SOLUTION: Solve the system using elimination.
2x − y + 3z = −2 [1]
−x + 2y − 3z = 10[2]
y + 5z = −6[3]
The solution to the system of three linear
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Question 1097960: Solve the system using elimination.
2x − y + 3z = −2 [1]
−x + 2y − 3z = 10[2]
y + 5z = −6[3]
The solution to the system of three linear equations is the ordered triple____.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
2x − y + 3z = −2
−x + 2y − 3z = 10
y + 5z = −6; z=-(1/5)y-(6/5)
add the first and second and x+y=8
multiply the first by 2 and add
4x-2y+6z=-4
-x+2y-3z=10
3x+3z=6
x+z=2; x-(.8y)-1.2=2
x-.8y=3.2
-x-y=-8
-1.8y=-4.8
y=8/3.
x=16/3
first equation 3z=-2; z=-2/3
tentatively have (8/3, 16/3, -2/3) ANSWER
That works in the second equation and also the third equation.
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