Question 1082665: x+y+z=12
x-y+z=6
x-y-z=o.
So x,y,and,z=?
Found 2 solutions by ikleyn, MathTherapy:
Answer by ikleyn(52786)   (Show Source):
You can put this solution on YOUR website! .
x + y + z = 12 (1)
x - y + z = 6 (2)
x - y - z = o. (3)
1) Subtract eq(2) from eq(1) (both sides). You will get 2y = 12 - 6 ---> y = 3.
2) Add eq(1) and eq(2). You will get 2x = 12 + 0 ---> x = 6.
3) Then from EITHER equation z = 3.
Solved.
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Comment from student: 2x+2y-z=10 x+y+z=11 2x+y-z=7 So x,y,z=?
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My response: Is this instead of "Thanks" ?
Answer by MathTherapy(10552)  (Show Source):
You can put this solution on YOUR website! x+y+z=12
x-y+z=6
x-y-z=o.
So x,y,and,z=?
x + y + z = 12 ----- eq (i)
x - y + z = 6 ------ eq (ii)
x - y - z = 0 ------ eq (iii)
1) ADD eqs (i) & (iii) to ELIMINATE y and z and find the value of x
2) Subtract eq (ii) from eq (i), or vice-versa to ELIMINATE x and z and find the value of y
3) Subtract eq (iii) from eq (ii) or vice-versa to ELIMINATE x and y and determine the value of z.
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