SOLUTION: Five years ago A age was four times the age of B. Five years hence A age will be the age of B find their present ages.

Question 1081755: Five years ago A age was four times the age of B. Five years hence A age will be the age of B find their present ages.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
As the problem is stated there is no solution.
Five years ago, A's age was 4 times that of B. That makes him older than B.
Yet, in 5 years A will be the same age that B is now. That makes him younger than B. He can't be both.
Maybe 5 years ago A's age, *4, was equal to B
4(A-5)=B
in 5 years, A's age will equal B's.
A+5=B
then 4A-20=A+5, substituting.
3A=25
A=8 1/3
B=13 1/3
5 years ago, A was 3 1/3, or 13/3. That is 1/4 th of B's age now.

RELATED QUESTIONS
Five years ago father's age was seven times his sons age. Ten years hence their ages will (answered by nerdybill)

seven years ago varun's age was five times the square of swati's age. three years hence... (answered by lwsshak3)

Five years ago, A's age was four times B's age, 6 years hence A's age to B's is 5:2. Find (answered by Maths68)

Five years ago. A's age was four times B's age, 6 years hence A's age to B's is 5:2. Find (answered by Maths68)

The age of A is five years more than B five years ago the ratio of their age was 3:2 find (answered by MathTherapy)

2 years ago a man's age was 3 times the square of his son's age .3 years hence his age... (answered by ptaylor)

four years ago, a man's age was three years more than thrice his son's age. fifteen years (answered by stanbon)

The age of a man 10 years hence was four times the age of his son. Father's age after 10... (answered by JulietG)

C's age is 6 more than the sum of the ages of A and B. Five years from now A will be half (answered by ankor@dixie-net.com)