SOLUTION: Find the center and radius of the circle whose graph passes through the points (-3,-5), (-9,-13), and (-2,-12). Hint: use the equation x^2+y^2+ax+by+c=0. I need help, I have vari

Question 1080854: Find the center and radius of the circle whose graph passes through the points (-3,-5), (-9,-13), and (-2,-12). Hint: use the equation x^2+y^2+ax+by+c=0.
I need help, I have various examples but they skip steps so I don't understand how to solve it.
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
You will make a system of equations with the form of each equation as , because the right-side member will be a computable value for each equation.

Each point gives a separate equation.

------continue and solve this system for a, b, and c.

(used online calculator at https://matrix.reshish.com/gauss-jordanElimination.php )

Use the equation formed using the found coefficients and convert the equation into standard equation form for a circle ( can mean, completing the squares) and read the center and radius from the equation.
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