.
Let x = time in hours for the faster pipe to fill the tank alone.
Then the time for the other pipe is (x+5) hours.
The faster pipe fills of the tank volume per hour.
The slower pipe fills of the tank volume per hour.
Working together, they fill of the tank volume per hour.
According to the condition,
= .
It is your equation to solve.
The first step is to multiply both sides by 5x*(x+5). You will get
5(x+5) + 5x = x*(x+5), or
5x + 25 + 5x = x^2 + 5x,
x^2 - 5x - 25 = 0.
= = .
= = 8.1 hours (approximately).
The second root is negative and doesn't work.
Check. = 0.2. Correct !
Answer. Faster pipe in 8.1 hours. Slower pipe in 13.1 hours.
Solved.
For a wide variety of similar solved joint-work problems with detailed explanations see the lessons
- Using Fractions to solve word problems on joint work
- Solving more complicated word problems on joint work
- Selected joint-work word problems from the archive
- Using quadratic equations to solve word problems on joint work (*)
in this site.
Read them and get be trained in solving joint-work problems.
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this textbook under the topic "Rate of work and joint work problems" of the section "Word problems".
The lesson in the list marked by (*) contains other similar solved problems relevant to yours.