Question 1066041: What is the distance between point (9,18) and the line 30x-15y=75 Found 4 solutions by josgarithmetic, stanbon, MathTherapy, ikleyn:Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website! What is the equation of the line through point (9,18) having slope ? Where does that line intersect with ? What is the distance between the two points (use the Distance Formula). Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website! What is the distance between point (9,18) and the line 30x-15y=75
Slope of given line:: m = 30/15 = 2
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Slope of perdicular line thru (9,18)
m = -1/2
Form:: y = mx+b
18 = (-1/2)9 + b
b = 22.5
Equation:: y = (-1/2)x+22.5
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Find intersection of the two lines::
y = 2x -5
y = (-1/2)x+22.5
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2x-5 = (-1/2)x+22.5
2.5x = 27.5
x = 11
y = 2x-5 = 22-5 = 17
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Distance from (9,18) to (11,17)
d = sqrt[(11-5)^2+(18-17)^2] = sqrt[37]
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Cheers,
Stan H.
----------- Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website! What is the distance between point (9,18) and the line 30x-15y=75
The 2 lines intersect at: (11, 17)
Distance from point (9, 18) to (11, 17), or
d, or PERPENDICULAR distance between (9, 18) and (11, 17) =
where a, b and c are real numbers, and let P = P(,) is the point in the coordinate plane
with the coordinates , . Then the distance from the point P to the straight line (1) is equal to