# SOLUTION: A system of linear equations has solutions (1, -1) and (-2,3). a)Can you find another solution? b)How many solutions must exist?

Algebra ->  Algebra  -> Coordinate Systems and Linear Equations -> SOLUTION: A system of linear equations has solutions (1, -1) and (-2,3). a)Can you find another solution? b)How many solutions must exist?      Log On

 Ad: You enter your algebra equation or inequality - Algebrator solves it step-by-step while providing clear explanations. Free on-line demo . Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Linear Solvers Practice Answers archive Word Problems Lessons In depth

 Click here to see ALL problems on Linear-systems Question 106514This question is from textbook Algebra 2 with trigonometry : A system of linear equations has solutions (1, -1) and (-2,3). a)Can you find another solution? b)How many solutions must exist?This question is from textbook Algebra 2 with trigonometry Answer by stanbon(57361)   (Show Source): You can put this solution on YOUR website!A system of linear equations has solutions (1, -1) and (-2,3). -------- The only way two lines can intersect in two points is when the two lines are really the same line. ------------ Your problem slope = -4/3 Then -1 = (-4/3)*1 + b b = -1 +(4/3) = 1/3 EQUATION: y = (-4/3)x + (1/3) -------------------- a)Can you find another solution? There are an infinite number of solutions: Let x=0 then y = (1/3) Let x = 3 then y = -11/3 etc. ----------- b)How many solutions must exist? An infinite number Cheers, Stan H.