SOLUTION: I would really appreciate some help with this question as I have tried and tried again, for the past few hours, to find out what the two equations are and I still cannot find out w

Question 1057011: I would really appreciate some help with this question as I have tried and tried again, for the past few hours, to find out what the two equations are and I still cannot find out what they are.
James is six times as old as his granddaughter, Louise. In two years time he will only be five time as old as Louise. Use simultaneous equations to determine how old James and Louise are now?
Found 3 solutions by josgarithmetic, solve_for_x, ikleyn:
Answer by josgarithmetic(39618)   (Show Source): You can put this solution on YOUR website!
James, j
Granddaughter Louise, g

Answer by solve_for_x(190)   (Show Source): You can put this solution on YOUR website!
Let J represent James' age, and let L represent Louise's age.

Since James is currently 6 times as old as Louise, you can write:
J = 6L

In two years time, both of their ages will have changed. James will be J + 2,
and Louise will be L + 2 years old.

At that time, James' age will be 5 times Louise's age, so you can write:

J + 2 = 5(L + 2)

This gives two equations that can be used to solve for the current ages of
James and Louise.

Answer by ikleyn(52790)   (Show Source): You can put this solution on YOUR website!
.
There is a bunch of lessons on age word problems
    - Age problems and their solutions
    - A fresh formulation of a traditional age problem
    - Really intricate age word problem
    - Selected age word problems from the archive
    - Age problem for the day of April, 1
    - OVERVIEW of lessons on age problems
in this site.

Read them and become an expert in solving age problems.

Also, you have this free of charge online textbook in ALGEBRA-I in this site
    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.

The referred lessons are the part of this online textbook under the topic "Age word problems".

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