SOLUTION: 1. In an opera theater, sections of seating consisting of three rows are being laid out. It is planned so each row will be two more seats than the one before it and 90 people must

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: 1. In an opera theater, sections of seating consisting of three rows are being laid out. It is planned so each row will be two more seats than the one before it and 90 people must       Log On


   



Question 1048787: 1. In an opera theater, sections of seating consisting of three rows are being laid out. It is planned so each row will be two more seats than the one before it and 90 people must be seated in each section. How many people wit be in the third row?
2. In the same opera theater personal balcony sections with three rows of seating are being mapped as well. In these sections there must be an odd number of seats in each row and each row have two more seats than the one before it. The last stipulation is that the front row must have one quarter the total seats in the back two rows combined. How many seats will be in each row?





Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
(1)
The number in each row is:
+n+, +n+%2B+2+, +n+%2B+4+
It is given that:
+n+%2B+n+%2B+2+%2B+n+%2B+4+=+90+
+3n+%2B+6+=+90+
+3n+=+84+
+n+=+28+
and
+n+%2B+2+=+30+
+n+%2B+4+=+32+
There are 32 people in the 3rd row
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check:
+28+%2B+30+%2B+32+=+90+
+90+=+90+
OK
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(2)
Let +n+ = number of seats in 1st row
+n+%2B+2+ seats in 2nd row
+n+%2B+4+ seats in 3rd row
and
+n+=+%281%2F4%29%2A%28+n+%2B+2+%2B+n+%2B+4+%29+
+4n+=+2n+%2B+6+
+2n+=+6+
+n+=+3+
and
+n+%2B+2+=+5+
+n+%2B+4+=+7+
The number of seats, front to rear, are 3, 5, and 7
check:
+3+=+%281%2F4%29%2A%28+5+%2B+7+%29+
+3+=+12%2F4+
+12+=+12+
OK