SOLUTION: If 2016 = 2^x*3^y*5^z*7^u are non negative integers, the value of x+y+2016z+3u will be a)10 b)11 c)12 d)13

Algebra ->  Coordinate Systems and Linear Equations -> SOLUTION: If 2016 = 2^x*3^y*5^z*7^u are non negative integers, the value of x+y+2016z+3u will be a)10 b)11 c)12 d)13      Log On


   

Question 1045324: If 2016 = 2^x*3^y*5^z*7^u are non negative integers, the value of x+y+2016z+3u will be a)10 b)11 c)12 d)13
Answer by ikleyn(52787) About Me  (Show Source):
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If 2016 = 2^x*3^y*5^z*7^u are non negative integers, the value of x+y+2016z+3u will be a)10 b)11 c)12 d)13
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2016 = 2%5E5%2A3%5E2%2A7.


Therefore,  If 2016 = 2^x*3^y*5^z*7^u, then x = 5, y = 2, z = 0 and u = 1.


Having this, you will easily find x + y + 2016z + 3u = 5 + 2 + 2016*0 + 3*1 = 10