SOLUTION: x>0 y>0. 3x+2y>18 6x+7y<42 What is the value of 3x+3y Thank you

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Question 1040255: x>0
y>0.
3x+2y>18
6x+7y<42
What is the value of 3x+3y
Thank you

Answer by ikleyn(52787)   (Show Source): You can put this solution on YOUR website!
.
x>0
y>0.
3x+2y>18
6x+7y<42
What is the value of 3x+3y
Thank you
~~~~~~~~~~~~~~~~~~~~~~




y = is red line; y = is the green line.
The set  {x>0 , y>0} is the first quadrant.

{3x + 2y > 18}    is the domain above the red line.

{6x + 7y < 42}    is the domain below the green line.

So, the intersection is this obtuse tiangle in the first quadrant adjacent to the x-axis.

I do not see much sense in the question of the problem.

You can estimate the range of this linear function z = 3x + 3y by evaluating its values in the vertices of the triangle.
(Then is it typical problem of the linear programming).

May be other tutors have some ideas?


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