SOLUTION: Find two consecutive even integers such that the lesser added to three times the greater gives a sum of 46.

Question 103178This question is from textbook beginning algebra
: Find two consecutive even integers such that the lesser added to three times the greater gives a sum of 46. This question is from textbook beginning algebra

Answer by doukungfoo(195) (Show Source): You can put this solution on YOUR website!
Lets call the first interger x
For the second interger to be a consecutive even interger it must be
x+2
Ok so far we have
first interger = x
second interger = x+2
Now lets look at what we are given:
Find two consecutive even integers such that the lesser added to three times the greater gives a sum of 46.
Using x for the first interger and x+2 for the second interger write and equation that satisfies this statement.
(x) + 3(x+2) = 46
Now just solve for x
(x) + 3(x+2) = 46
multiply 3 across (x+2)
x + 3x + 6 = 46
combine like terms
4x + 6 = 46
subtract 6 from both sides
4x = 40
divide both sides by 4
x = 10
Answer: the first interger is 10
so if the first interger is 10 then the second interger is 12 because
second interger = x+2
second interger = 10+2
second interger = 12
Answer: the second interger is 12
check answers:
Find two consecutive even integers such that the lesser added to three times the greater gives a sum of 46.
10 + 3(12) = 46
10 + 36 = 46
46 = 46

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