SOLUTION: 5x+y+6z = −1 4x−y+4z = 1 3x−y+4z = −9 what is x, y , z?
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-> SOLUTION: 5x+y+6z = −1 4x−y+4z = 1 3x−y+4z = −9 what is x, y , z?
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Question 1030661
:
5x+y+6z = −1
4x−y+4z = 1
3x−y+4z = −9
what is x, y , z?
Answer by
josgarithmetic(39617)
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You can make a substitution for y in two of the equations, if you are not required to use matrix operations. You will have a two-variable linear system, easily solved.