Solve 3x+2y = 1 for ySubstitute in Substitute (-1+2i) in One solution is (-1+2i, 2-3i) Substituting (-1-2i) the same way gives 2+3i So the other solution is (-1-2i, 2+3i) These solutions are complex imaginary, so the graphs should not cross: And, as we see the black line, which is the graph of , does not cross the red hyperbola, which is the graph of Edwin