SOLUTION: solve 2x^2-3x-14=0
Algebra.Com
Question 101413: solve 2x^2-3x-14=0
Answer by oberobic(2304) (Show Source): You can put this solution on YOUR website!
The first approach is to try to factor it.
You know you will have: (2x )(x ) for the x terms. And since the constant is negative, one of the factors will have a - and the other will have a +.
You know that 14 = 2 * 7, which are your only choices.
So the only choices are
(2x + 2)(x - 7)
(2x - 2)(x + 7)
(2x + 7)(x - 2)
(2x - 7)(x + 2)
You're looking to the -3x, which is:'
(2x - 7)(x + 2)
ALWAYS check!
(2x - 7)(x + 2) = 2x*x + 2x*2 - 7*x - 7*2 = 2x^2 + 4x - 7x - 14 = 2x^2 - 3x - 14.
RELATED QUESTIONS
Solve. (x – 3)^2 = 2
Solve. 2x^2 – 8x – 14 = 0
Solve. 3x^2 = –21x – 15
(answered by sofiyac)
solve... (answered by jim_thompson5910)
solve... (answered by jim_thompson5910)
Solve the equation: 2x^2 - 3x =... (answered by jim_thompson5910)
Solve:... (answered by jim_thompson5910)
Solve
2x^2 + 3x − 5 = 0
(answered by scott8148)
Solve the equation below.
Please enter your answer as two numbers, separated by a... (answered by scott8148)
Solve 3x^2 + 19x-14=0 using the quadratic formula
(answered by stanbon)
solve
2x^2 - 3x - 2 = 0 using quadratic... (answered by Edwin McCravy)