SOLUTION: A hospital need 80 L of a 12% solution of disinfectant. How many liters of a 33% solution and a 5% solution should be mixed to obtain this 12% solution? Fill in the following table

Question 1005864: A hospital need 80 L of a 12% solution of disinfectant. How many liters of a 33% solution and a 5% solution should be mixed to obtain this 12% solution? Fill in the following table and solve for x and y.
PERCENT PER LITER X Number of Liters = Amount of disinfectant
33% solution 0.33 X x = 0.33x
5% solution 0.05 X y =
12% mixture 0.12 X 80 =
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
two-part mixture using one variable - video example showing method

Lesson on Two-Part Mixtures, percent concentrations, using two variableshttp://www.algebra.com/my/Mixtures%3A-All-in-Symbols.lesson?content_action=show_dev
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