SOLUTION: Graph 3x+y <5

Algebra.Com
Question 865120: Graph 3x+y <5
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
To graph we first need to graph











This line has a slope of -3 and a y-intercept of 5. This is the point (0,5). Another point on this line is (1,2). You would start at (0,5) and go down 3 and over to the right 1 to get to (1,2)


So plot (0,5) and (1,2). Draw a dashed line through these two points. This is the boundary of the shaded region and the dashed line means we are NOT including the boundary line in the solution set.


If you were to solve for y, you'd get and you follow the same basic steps as shown above.


Since the inequality sign is a less than sign, we shade below the dashed line.


To summarize, we have a dashed line and we are shading below the dashed line. This dashed line goes through (0,5) and (1,2)

RELATED QUESTIONS

Graph y = 3x –... (answered by jim_thompson5910)
Graph... (answered by user_dude2008)
Graph... (answered by jim_thompson5910)
1. Graph y = 3x –... (answered by jim_thompson5910)
please graph... (answered by jim_thompson5910)
graph y=-2/3x+5 (answered by MathLover1,Edwin McCravy,mccravyedwin)
Graph y=-3x... (answered by mananth)
Graph y=-5/3x+3 and... (answered by MathLover1)
Graph the inequality. 3x + y ≤... (answered by bucky)