SOLUTION: how do i convert 4 cups/min=qt/min 18 mi/hr= ft/sec 4.8 qt/min=gal/hr 7 cups/min=qt/hr thank you for all your help, I honestly do not know how to help my daughter.

Question 698222: how do i convert
4 cups/min=qt/min
18 mi/hr= ft/sec
4.8 qt/min=gal/hr
7 cups/min=qt/hr
thank you for all your help, I honestly do not know how to help my daughter.
Found 2 solutions by ankor@dixie-net.com, MathLover1:
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
convert
4 cups/min=qt/min
There are 4 cups in 1 quart, therefore
4 cups/min = 1 qt/min
:
18 mi/hr = ft/sec
Convert mi to ft by mult by 5280, divide that by no. of sec in 1 hr (3600)
= 26.4 ft/sec
:
4.8 qt/min = gal/hr
there are 4 qts in 1 gal, 60 min in 1 hr; therefore
* 72 = gal/hr
:
7 cups/min = qt/hr
there are 4 cups in a quart, 60 min 1 hr; therefore:
* 60 = 105 qt/hr
Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!
1.

so,
2.
AMP Parsing Error of [18(mil/hr)= x(ft/sec)]: Invalid function ')': opening bracket expected at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 70. . .... convert to multiplying your speed by which is AMP Parsing Error of [mil/h=5280ft/3600sec=1.4666666666666666666666666666667=1.467 (ft/sec)]: Invalid function '=1.4666666666666666666666666666667=1.467(ft/sec)': opening bracket expected at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 70. .

AMP Parsing Error of [18(mil/hr)=26.4(ft/sec)
3.
4.___4.8(qt/min)=x(gal/hr)]: Invalid function ')3.4.___4.8(qt/min)=x(gal/hr)': opening bracket expected at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 70. . ........ and

4.
....... [Fluid, US]

=
=
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