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Algebra.Com
Question 572185:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
A = ab*sin(theta)/2
13 = 7b*sin(60)/2
13 = 7b*(sqrt(3)/2)/2
13 = 7b*(sqrt(3)/4)
13*4 = 7b*sqrt(3)
52 = 7b*sqrt(3)
52/(7*sqrt(3)) = b
b = (52*sqrt(3))/21
So the answer is
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