Hi

two consecutive integers

Let x and (x+1) represent the two consecutive integers

Question states***

 x +(x+1)= x(x+1)-19

Solving for x

 2x + 1 = x^2 + x - 19

  x^2 -x - 20 = 0 

factoring

 (x-5)(x+4)= 0 Note:SUM of the inner product(-5x) and the outer product(4x) = -x

(x-5)=0   x = 5, the two consecutive integers are 5 and 6

(x+4)= 0  x = -4 the two consecutive integers are -4 and -3



CHECKING our Answer(s)***

 5 + 6 = 30 - 19

 -4 - 3 = -4*-3 - 19 

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