SOLUTION: Please help me I am stuck here trying to figure out some algebra the question is a rectangle has a length of 4x and a width of 4x-2. Its perimeter is 12 inchs. find the length and

Question 309863: Please help me I am stuck here trying to figure out some algebra the question is a rectangle has a length of 4x and a width of 4x-2. Its perimeter is 12 inchs. find the length and width
Found 2 solutions by nerdybill, MathTherapy:
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
a rectangle has a length of 4x and a width of 4x-2. Its perimeter is 12 inchs. find the length and width
.
Since perimeter of any rectangle:
length + length + width + width = perimeter
2length + 2width = perimeter
2(length + width) = perimeter
.
Substitute what was given:
length = 4x
width = 2x-2
perimeter = 12
.
2(4x + 2x-2) = 12
2(6x-2) = 12
6x-2 = 6
6x = 8
x = 8/6
x = 4/3
.
length = 4x = 4(4/3) = 16/3 inches
width = 2x-2 = 2(4/3)-2 = 8/3 -2 = 8/3 - 6/3 = 2/3 inches
.

Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
Please help me I am stuck here trying to figure out some algebra the question is a rectangle has a length of 4x and a width of 4x-2. Its perimeter is 12 inchs. find the length and width

If length = L, and width = W, then = 2L + 2W = Perimeter, or, 2L + 2W = 12

Since length = 4x, and width = 4x - 2, then we'll have:

2(4x) + 2(4x - 2) = 12

8x + 8x - 4 = 12

16x = 16

x = = 1

Length is therefore 4(1) or , and width = 4(1) - 2, or
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