Questions on Algebra: Unit Conversion answered by real tutors!

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Question 115771: solve for y in 6x-5y=-5. determine if the line is parallel to y=6/5x+5/9: solve for y in 6x-5y=-5. determine if the line is parallel to y=6/5x+5/9
Answer by edjones(2401) About Me  (Show Source):
You can put this solution on YOUR website!
y=mx+b m=slope
y=6x/5+5/9 m=6/5
If the next equation has the same slope they are parallel.
6x-5y=-5
6x-6x-5y=-6x-5
-5y=-6x-5
-5y/-5=-6x/-5 -5/-5
y=6x/5+1 m=6/5
They are parallel.
.
Ed
Question 115771: solve for y in 6x-5y=-5. determine if the line is parallel to y=6/5x+5/9: solve for y in 6x-5y=-5. determine if the line is parallel to y=6/5x+5/9
Answer by bucky(1732) About Me  (Show Source):
You can put this solution on YOUR website!
One step at a time. First, solve the equation 6x - 5y = -5 for y:
.
Begin by getting rid of the term 6x on the left side so that you just have the term containing
the y alone on the left side. Do this by subtracting 6x from both sides to get:
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-5y = -6x - 5
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You are trying to solve for +y so at this point you may want to change the sign of -5y to +5y.
You can do that by multiplying both sides of the equation (all terms) by -1 to change the
equation to:
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5y = 6x + 5
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Finally, solve for y by dividing both sides of this equation by 5 ... the multiplier of
y to get:
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y = (6/5)*x + 5/5 = (6/5)*x + 1
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Notice that the equation we now have is:
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y =  (6/5)*x + 1
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and this is in the slope-intercept form:
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y = mx + b
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in which m, the multiplier of x, is the slope of the graph and b is the value on the y-axis
where the graph crosses the y-axis. By comparing your equation with the slope intercept form
you can see that the graph of your equation has a slope of (6/5) and it crosses the
y-axis at the value of +1 on the y-axis.
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Now look at the other equation you were given ... namely:
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y = (6/5)*x + 5/9
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Comparing this equation to the slope intercept form you will see that it also has a slope
of 6/5 but its graph crosses the y-axis at 5/9.
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Now recognize that two graphs having the same slope but different crossing points on the
y-axis are parallel lines that are always separated in vertical distance by an amount equal
to the difference on the y-axis equal to the crossing points. The graph of the two equations
shows this. The "red" graph is the graph of the equation y = (6/5)*x + 1 and the green
graph is the graph of the equation y = (6/5)*x + 5/9
.
graph(800,800,-15,15,-15,15,(6/5)*x + 1,(6/5)*x + 5/9)
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Hope this helps you to understand the problem and shows you that lines given by the two equations
are actually parallel.
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