SOLUTION: You want to put a 5 inch thick layer of topsoil for a new 22 ft by 27 ft garden. The dirt store sells by the cubic yards. How many cubic yards will you need to order? The store onl

Question 1150362: You want to put a 5 inch thick layer of topsoil for a new 22 ft by 27 ft garden. The dirt store sells by the cubic yards. How many cubic yards will you need to order? The store only sells in increments of 1/4 cubic yards.
cubic yards
Answer by MathsterChief (3) (Show Source): You can put this solution on YOUR website!
Lets first make sure all units are consistent. For the purposes of this problem, let's work with Feet.
Thickness = 5 inches = 5/12ft
Area = 22ftx27ft =
Therefore volume of dirt needed to fill the yard is Area x Thickness =
We can calculate the volume of dirt in each "order" by converting to ft
1/4 cubic yards = (1 yard = 3 feet) >> =
To find how many bags of orders we need we divide (total volume needed) by (volume of dirt in each order)
Solving gives So we will round to the next whole number and will need 37 orders of dirt.
RELATED QUESTIONS
You want to put a 2-inch thick layer of topsoil for a new 30 ft by 22 ft garden. The dirt (answered by ikleyn)

You want to put a 3 inch thick layer of topsoil for a new 31 ft by 30 ft garden. The dirt (answered by josgarithmetic)

You want to put a 2 inch thick layer of topsoil for a new 13 ft by 14 ft garden. The dirt (answered by ikleyn)

You want to put a 2" thick layer of topsoil for a new 20'x30' garden. The dirt store... (answered by josgarithmetic)

Here is a better example: You are putting a fence in your yard to separate your property (answered by Mathtut,mathTurtle)

He has decided to remove all the old sod (grass), bring in a new 4 inch layer of... (answered by Solver92311)

He has decided to remove all the old sod (grass), bring in a new 4 inch layer of... (answered by mananth)

Dirt is to be removed from a foundation that is 120 ft long, 60 ft wide, and 12 ft deep... (answered by josgarithmetic)

Construction: Dirt must be excavated for the foundation of a building 30 yards by 15... (answered by stanbon)